Electronics - Voltage and Current - Discussion

Discussion Forum : Voltage and Current - General Questions (Q.No. 9)
9.
In practical applications, battery voltage:
is restored as soon as disconnect occurs
is lowered as the load increases
may be stored indefinitely
will be reduced to zero as power is drawn
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
45 comments Page 2 of 5.

Shubham said:   1 decade ago
Which law should we apply here.

V=IR.
P=VI.

Please ans. Which is correct.

Charan said:   1 decade ago
In real time, any running with any load for racer will decrease his real speed due to weight.

Swapnajit said:   1 decade ago
According to ohms law voltage is directly to propotional to current.

V= IR.

As as "R" increases so I will be less for const voltage supply. I less means we less (directly propotional).

Gaurav said:   1 decade ago
For ideal constant voltage source, voltage willnot change. But in practical it decreses as load increases. And power need to be constant.

Shahir said:   1 decade ago
Prasanth answer is wrong. As current increase voltage also increase and vice versa.

Raviteja said:   1 decade ago
It is just like a inverter when ever the power supply is on it will get charged and as soon as the power supply goes off the battery will be enabled and the stored charge will decay exponentially

Saroj kumar said:   1 decade ago
Think practical as we increase load current will draws more rapidly.

Sreeyush Sudhakaran said:   1 decade ago
Consider you as battery and load as sack lifted by you

When ever number of sacks(Load) increases your energy(battry voltage) decreses gradually.

Ranjith Garuda said:   1 decade ago
Electrical energy gets dissipated as heat through load.(more precisely electrical energy gets converted into heat energy) more the load more energy is spent battery certainly loose energy very fast.

Example: the battery in your digital watch will run for a long time, when you connect the same set of battery to a completely resistance load like a LED light it will drain with in minutes. Energy dissipation in that watch was less but in LED it was more, more energy was spent to drive the LED.

(more the load more the power dissipation. Its a natural phenomenon no need to break it through ohms law)

Battery voltage gets lowered when load increases.

Rajasekhar said:   1 decade ago
What is difference between voltage and current?


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