Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 7)
7.
Calculate the voltage at point B in the given circuit.
Discussion:
36 comments Page 4 of 4.
Gopiram Verma said:
1 decade ago
Ya Rishi is right.
Rishi pandey said:
1 decade ago
I=(12-9)/150= 0.02mA
let 9V as GND then Potential at B= (47+27)K * 0.02mA =1.48V
so pot. at B if GND is 0V =9V+1.48V =10.48V
let 9V as GND then Potential at B= (47+27)K * 0.02mA =1.48V
so pot. at B if GND is 0V =9V+1.48V =10.48V
Rizwan said:
1 decade ago
Please Explain how the voltage of these batteries adding?
Atif said:
1 decade ago
The batteries are connected in series opposing configuration, Then how voltages can b add?
Bhanu said:
1 decade ago
Here the net voltage should be 12-9 or 9-12. Why.
Because both the facing polarities are same.
Because both the facing polarities are same.
Aneeshrajan said:
1 decade ago
I=21/150
V1=74*21/150
V2=76*21/150
V at B=(V1+V2)/2=10.5
V1=74*21/150
V2=76*21/150
V at B=(V1+V2)/2=10.5
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