Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 9)
9.
What is the voltage at points B to D in the given circuit?
Discussion:
14 comments Page 2 of 2.
Dhaval Makhecha said:
1 decade ago
V=28v
R=R1+R2+R3=7kohm
I=V/R= 28/7= 4 ma.
Now, voltage between point B and D,
V=I(R2+R3) = 4(3.3+1.5) = 4*4.8 = 19.2v
So, V=19.2v
R=R1+R2+R3=7kohm
I=V/R= 28/7= 4 ma.
Now, voltage between point B and D,
V=I(R2+R3) = 4(3.3+1.5) = 4*4.8 = 19.2v
So, V=19.2v
Vijayakumar said:
1 decade ago
V = 28v.
R = R1+R2+R3 = 7kohm.
I = V/R = 28/7 = 4 ma.
Vb = iR2 = 4*3.3 = 13.2.
Vd = iR3 = 4*1.5 = 6.
V = Vb+Vd = 13.2+6 = 19.2V.
R = R1+R2+R3 = 7kohm.
I = V/R = 28/7 = 4 ma.
Vb = iR2 = 4*3.3 = 13.2.
Vd = iR3 = 4*1.5 = 6.
V = Vb+Vd = 13.2+6 = 19.2V.
(1)
Saichaitanya said:
1 decade ago
As per the voltage Divider rule:
V= (R1 + R2) (Total Voltage/(R1+R2+R3))
V= (3.3K + 1.5K) (28/(2.2K + 3.2K + 1.5K))
V=19.2 V
V= (R1 + R2) (Total Voltage/(R1+R2+R3))
V= (3.3K + 1.5K) (28/(2.2K + 3.2K + 1.5K))
V=19.2 V
Faizan said:
7 years ago
v = i * r = 28/7 * 4.8 = 19.2.
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers