Electronics - Series Circuits - Discussion

As per the voltage Divider rule:

V= (R1 + R2) (Total Voltage/(R1+R2+R3))

V= (3.3K + 1.5K) (28/(2.2K + 3.2K + 1.5K))

V=19.2 V

OR
V=28v
R=R1+R2+R3=7kohm

I=V/R= 28/7= 4 ma.

Now, voltage between point B and D,

V=I(R2+R3) = 4(3.3+1.5) = 4*4.8 = 19.2v

So, V=19.2v

Dear mats,
we have,
R1=2.2kohms,R2=3.3Kohms,R3=1.5Kohms,
convert it into ohms,then,
R1=2200ohms,R2=3300Ohms,R3=1500Ohms,R=(R1+R2+R3)=7000 Ohms
V=28v,
so I from the wquation V=IR,
I=V/R,
I=28v/7000 ohms,
I=0.004A,
And we have to find the voltage betwean B and D,
Resisters b/w B&D are R2&R3,So
V b/w B&D is V=I(R2+R3),
V=0.004(3300ohms+1500ohms),
V=19.2v.

V=IR then total resistance R=(R1+R2+R3).

Then R=(2.2+3.3+1.5), R=7Kohm, V=IR, I=28/7, I=4ma.

Now points b and d the total resistane Rbd=3.3+1.5=4.8kohm.
Now V=IR,4*4.8=19.2.

Am I Right?

V = I*R.

Given V = 28V.

R equivalent = 7K.

Therefore I = V/R = 4mA.

Res from B to D = 4.8K.

V from B to D = I*Res =4*4.8*10^3*10^-3 = 19.2.