Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 5)
5.
What is the Q (Quality factor) of a series circuit that resonates at 6 kHz, has equal reactance of 4 kilo-ohms each, and a resistor value of 50 ohms?
Discussion:
16 comments Page 2 of 2.
Ram charan said:
9 years ago
Q = xL/R
= 4k/50
= 4000/50
= 80 ohms.
= 4k/50
= 4000/50
= 80 ohms.
(1)
Pawan siddh said:
8 years ago
Q=XL/R.
4000/50 = 80ans.
4000/50 = 80ans.
Neha said:
1 decade ago
Please explain.
Ashutosh singh said:
8 years ago
Her, Q = Xl/R.
Aruna said:
5 years ago
Q = XL/R.
Deepak said:
1 decade ago
Q=XL/R
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