Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 1)
1.
What is the applied voltage for a series RLC circuit when IT = 3 mA, VL = 30 V, VC = 18 V, and R = 1000 ohms?
Discussion:
37 comments Page 3 of 4.
Ankur said:
1 decade ago
We have relation
Vm= (VR^2+(VL-VC)^2)^1/2
VR= I*R=3*10^-3 * 1000 = 3 volts
VL= 30 volts
VC= 18 volts
therefore, Vm= 12.37
Vm= (VR^2+(VL-VC)^2)^1/2
VR= I*R=3*10^-3 * 1000 = 3 volts
VL= 30 volts
VC= 18 volts
therefore, Vm= 12.37
Ch manikantha said:
9 years ago
Vr = i * r =3mA * 1k = 3v
Vs = √(Vr^2 + (Vc - Vl)^2).
Vs = √(3^2 + (30 - 18)^2) = 12.36.
Vs = √(Vr^2 + (Vc - Vl)^2).
Vs = √(3^2 + (30 - 18)^2) = 12.36.
Surya said:
1 decade ago
Can anyone please difference between impedance and resistance. Can we write v = i*z (z=impedance ).
Nilesh said:
1 decade ago
vs=squrt(squr(It*r)+squar(Vl-Vc))
=squrt(squr(3*1000*0.001)+squr(30-18))
=squrt(9+144)
=12.37V
=squrt(squr(3*1000*0.001)+squr(30-18))
=squrt(9+144)
=12.37V
Stanley said:
1 decade ago
Lets train ourselves to use SI units always, by so doing you will not mess. Thanks.
G.Satish Kumar said:
7 years ago
V^2 = Vr^2+(VL-VC)^2.
V^2 = 3^2+(30-18)^2,
=9+144,
V^2= 153.
V = 12.369.
V^2 = 3^2+(30-18)^2,
=9+144,
V^2= 153.
V = 12.369.
(4)
Khan said:
9 years ago
VL = 30 <90, VC =1 8<-9 0, VR = 3.
hence V = sqrt(12^2 + 3^2) = 12.37.
hence V = sqrt(12^2 + 3^2) = 12.37.
LALIT GARG said:
1 decade ago
VL=I*XL , VC=I*XC
XL=?,XC=?,R=1000
Z=UNDERROOT OF R2+(XC-XL)2
V=I*Z=12.37
XL=?,XC=?,R=1000
Z=UNDERROOT OF R2+(XC-XL)2
V=I*Z=12.37
Mahu said:
10 years ago
By tricky its sure answer will be A or B but why B tell me please.
Manikanta said:
1 decade ago
Why can't we write kvl for this but I'm not getting answer.
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