Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 1)
1.
What is the applied voltage for a series RLC circuit when IT = 3 mA, VL = 30 V, VC = 18 V, and R = 1000 ohms?
Discussion:
37 comments Page 3 of 4.
Swathi said:
1 decade ago
XL=VL/I=10 and XC=VC/I=6
Z=sqrt of (100)2+(6-10)2=10016 i got
V=I*Z
=3*10016
=300.239904077 i got but the given answer is not come how to solve to get that answer.
Z=sqrt of (100)2+(6-10)2=10016 i got
V=I*Z
=3*10016
=300.239904077 i got but the given answer is not come how to solve to get that answer.
Vinodhine said:
1 decade ago
Swathi, you have to consider the R value as 1 Kohm, and dont forget to note the current is in milliampere so resistance will be in Kiloohms
Siva said:
1 decade ago
Vinodhine is correct.
Hussain said:
1 decade ago
Vinodhine the value of R = 1000 that is 1K but u have taken as 100.
Galit garg is right.
I = v/z => v = I * z = 3m * sqrt(17)*k = 3 * 4.123 = 12.37v
Galit garg is right.
I = v/z => v = I * z = 3m * sqrt(17)*k = 3 * 4.123 = 12.37v
Amulya said:
1 decade ago
If we do them as if they are easy they will be easy...n if we think them to be difficult they will be difficult.....ALL THE BEST FRNDS...!!!!!!!!!
V=IZ
z=impedence
Z=(R^2+(XL-XC)^2)^1/2
XL=VL/I=10000
XC=VC/I=6000 ----> Z=4123.1056
V=4123.1056*3*10^-3
V=12.369
V=IZ
z=impedence
Z=(R^2+(XL-XC)^2)^1/2
XL=VL/I=10000
XC=VC/I=6000 ----> Z=4123.1056
V=4123.1056*3*10^-3
V=12.369
Sarojini said:
1 decade ago
Hussain is correct.
Ankur said:
1 decade ago
We have relation
Vm= (VR^2+(VL-VC)^2)^1/2
VR= I*R=3*10^-3 * 1000 = 3 volts
VL= 30 volts
VC= 18 volts
therefore, Vm= 12.37
Vm= (VR^2+(VL-VC)^2)^1/2
VR= I*R=3*10^-3 * 1000 = 3 volts
VL= 30 volts
VC= 18 volts
therefore, Vm= 12.37
Stanley said:
1 decade ago
Lets train ourselves to use SI units always, by so doing you will not mess. Thanks.
LALIT GARG said:
1 decade ago
VL=I*XL , VC=I*XC
XL=?,XC=?,R=1000
Z=UNDERROOT OF R2+(XC-XL)2
V=I*Z=12.37
XL=?,XC=?,R=1000
Z=UNDERROOT OF R2+(XC-XL)2
V=I*Z=12.37
Yugandhar said:
1 decade ago
VR=3v;
vl=30v;
vc=18v;
vi=(3^2+(30-18)^2)^1/2;
vl=30v;
vc=18v;
vi=(3^2+(30-18)^2)^1/2;
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