Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 1)
1.
What is the applied voltage for a series RLC circuit when IT = 3 mA, VL = 30 V, VC = 18 V, and R = 1000 ohms?
Discussion:
37 comments Page 3 of 4.
Surya said:
1 decade ago
Can anyone please difference between impedance and resistance. Can we write v = i*z (z=impedance ).
Govind Singh Chouhan said:
1 decade ago
Given data:
R = 1000R.
Vc = 18V.
VL = 30V.
I = 3mA.
We know that,
Z=sqrt((R2)+(XL-XC)2)
And XL = VL/I ==> 30/0.003 = 10K.
And XC = VC/I ==> 18/0.003 = 6K.
So know put the value of XL and XC in in formula of Z so we can say that:
Z = sqrt(10002+(10K-6K)2)
Z = sqrt(1000000+16000000)
Z = sqrt(17000000)
Z = 4123 or
Z = 4.123K.
Now it applied voltage to the circuit is:
V=I*Z
V=0.003*4123
V=12.369 or 12.37V.
So applied voltage to this circuit is 12.37V.
Thanks.
R = 1000R.
Vc = 18V.
VL = 30V.
I = 3mA.
We know that,
Z=sqrt((R2)+(XL-XC)2)
And XL = VL/I ==> 30/0.003 = 10K.
And XC = VC/I ==> 18/0.003 = 6K.
So know put the value of XL and XC in in formula of Z so we can say that:
Z = sqrt(10002+(10K-6K)2)
Z = sqrt(1000000+16000000)
Z = sqrt(17000000)
Z = 4123 or
Z = 4.123K.
Now it applied voltage to the circuit is:
V=I*Z
V=0.003*4123
V=12.369 or 12.37V.
So applied voltage to this circuit is 12.37V.
Thanks.
Swapnil said:
1 decade ago
Vr = 1000*10^-3 = 3v.
VL = 30v.
vc = 18v.
V = square root of(3^2+(30-18)^2).
= square root of (9+144).
= square root of (153).
= 12.3691.
Answer = B.
VL = 30v.
vc = 18v.
V = square root of(3^2+(30-18)^2).
= square root of (9+144).
= square root of (153).
= 12.3691.
Answer = B.
Vinit said:
1 decade ago
E = I*R.
E = 0.003*1000.
E = 3 volts.
The reactive volts are:
VX = VL - VC.
VX = 30 - 18.
VX = 12 volts.
The applied volts is:
Volts = Sqrt(VR^2 + VX^2).
Volts = Sqrt (3^2 + 12^2).
Volts = Sqrt(153).
Volts = 12.3693.
E = 0.003*1000.
E = 3 volts.
The reactive volts are:
VX = VL - VC.
VX = 30 - 18.
VX = 12 volts.
The applied volts is:
Volts = Sqrt(VR^2 + VX^2).
Volts = Sqrt (3^2 + 12^2).
Volts = Sqrt(153).
Volts = 12.3693.
ANIL SINGH said:
10 years ago
Vr = IxR = 0.003 Ampx1000 Ohms = 3 Volts.
Now we have VL = 30V, Vc = 18V and Vr = 3V.
Applied voltage is given by.
Vs = SQRT of [Vr^2 + (VL-Vc) ^2].
= [3^2 + (30-18) ^2] = [9 + (12^2) ] = [9 + 144] = 153.
Therefore Vs = Square root of 153.
Vs = 12.369 Volts or Say 12.37 Volts here is the answer.
Now we have VL = 30V, Vc = 18V and Vr = 3V.
Applied voltage is given by.
Vs = SQRT of [Vr^2 + (VL-Vc) ^2].
= [3^2 + (30-18) ^2] = [9 + (12^2) ] = [9 + 144] = 153.
Therefore Vs = Square root of 153.
Vs = 12.369 Volts or Say 12.37 Volts here is the answer.
Mahu said:
10 years ago
By tricky its sure answer will be A or B but why B tell me please.
Leelavathi said:
9 years ago
Firstly the formula is v = IZ.
Xl = vl/I = 30/3*10^-3 = 10,000.
Xc = vc/I = 18/3*10^-3 = 6000.
Z = sqr of (R^2 + (xl-xc)).
Z = sqr of (1000^2 + (10000-6000)).
Z = sqr of (1004000) = 1001.998004.
Now,
V = 3 * 10^-3 * 1001.998004 = 3.005994.
Approximately ans = 3.00 v.
I don't know whether my answer is right or wrong. If I am wrong, please tell me my mistake.
Xl = vl/I = 30/3*10^-3 = 10,000.
Xc = vc/I = 18/3*10^-3 = 6000.
Z = sqr of (R^2 + (xl-xc)).
Z = sqr of (1000^2 + (10000-6000)).
Z = sqr of (1004000) = 1001.998004.
Now,
V = 3 * 10^-3 * 1001.998004 = 3.005994.
Approximately ans = 3.00 v.
I don't know whether my answer is right or wrong. If I am wrong, please tell me my mistake.
Khan said:
9 years ago
VL = 30 <90, VC =1 8<-9 0, VR = 3.
hence V = sqrt(12^2 + 3^2) = 12.37.
hence V = sqrt(12^2 + 3^2) = 12.37.
Weerasinghege maduka said:
9 years ago
Create voltare trangle.
v^2 = (VL-VC)^2 + VR^2
So,
VR= I * R
VR= 3mA*1000Ohms
VR=3V
V^2=(XL-XC)^2+VR^2,
=(30-18)^2+3^2,
=12^2 + 9,
=144 + 9,
=> V^2 = 153.
V = 12.36.
v^2 = (VL-VC)^2 + VR^2
So,
VR= I * R
VR= 3mA*1000Ohms
VR=3V
V^2=(XL-XC)^2+VR^2,
=(30-18)^2+3^2,
=12^2 + 9,
=144 + 9,
=> V^2 = 153.
V = 12.36.
Ch manikantha said:
9 years ago
Vr = i * r =3mA * 1k = 3v
Vs = √(Vr^2 + (Vc - Vl)^2).
Vs = √(3^2 + (30 - 18)^2) = 12.36.
Vs = √(Vr^2 + (Vc - Vl)^2).
Vs = √(3^2 + (30 - 18)^2) = 12.36.
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