Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 9)
9.
If two parallel-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss?
Discussion:
28 comments Page 3 of 3.
Sriram said:
1 decade ago
I go with Chandrasekhar.
Chandrasekhar said:
1 decade ago
Total power loss in a circuit is nothing but the power loss in the individual components =component1 power + component2 power loss.
The above statement is said because the energy cannot be created or destroyed.
The above statement is said because the energy cannot be created or destroyed.
Aman said:
1 decade ago
Power is additive in any configuration of resistive circuit: PTotal = P1 + P2 + . . . Pn
Abbu said:
1 decade ago
Then take current constant and calculate resistance.
Sandeep said:
1 decade ago
@Sujabanu
If power in series ckt's then o/p power. ?
If power in series ckt's then o/p power. ?
Sujabanu said:
1 decade ago
In parallel circuit, dissipate the power is same. So p1+p2=6+10=16.
Shiv said:
1 decade ago
P1=(V*V)/R1=6
P2=(V*V)/R2=10
=>R1=(5/3)R2
R=R1||R2=(5/8)R2
P=(V*V)/R=16
P2=(V*V)/R2=10
=>R1=(5/3)R2
R=R1||R2=(5/8)R2
P=(V*V)/R=16
Prakasam said:
1 decade ago
Power= P1+P2=6+10=16
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