Electronics - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 9)
9.
If two parallel-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss?
3.75 watts
4 watts
16 watts
60 watts
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
28 comments Page 2 of 3.

Ravi said:   1 decade ago
We know that P = V2R relation in parallel circuit v constant. So addition gives total power.

Salman said:   8 years ago
In parallel P=p1+p2.
In series P=p1.p2/p1+p2.

It is same as how we calculate capacitance.

Khalid usman pak said:   1 decade ago
In series circuit, always power equals p(total) = p1*p2/(p1+p2). Here the answer is 3.75.

Aman said:   1 decade ago
Power is additive in any configuration of resistive circuit: PTotal = P1 + P2 + . . . Pn

Mahantesh aadi said:   1 decade ago
If in series connected resistors dissipate 6w and 10w, which is right answer?

Shiv said:   1 decade ago
P1=(V*V)/R1=6
P2=(V*V)/R2=10
=>R1=(5/3)R2
R=R1||R2=(5/8)R2
P=(V*V)/R=16

Akshay Prakash said:   1 decade ago
SAMI total power dissipated will be always sum of individual power.

Sujabanu said:   1 decade ago
In parallel circuit, dissipate the power is same. So p1+p2=6+10=16.

Satyendra shgal said:   10 years ago
Power adding in any configuration simply add that Pn = P1 + P2.

Arshad said:   1 decade ago
Can you tell me how it is 4 watts? can you explain with calc?


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