Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 9)
9.
If two parallel-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss?
Discussion:
28 comments Page 2 of 3.
Khalid usman pak said:
1 decade ago
In series circuit, always power equals p(total) = p1*p2/(p1+p2). Here the answer is 3.75.
Kiran said:
1 decade ago
Is the total power loss equal to the average power loss ?
Bharat Malik said:
1 decade ago
P=VI and V is constant in parallel circuit. So P is directly propositional to I. So P=P1+P2 So 10+6=16 watts.
Akshay Prakash said:
1 decade ago
SAMI total power dissipated will be always sum of individual power.
Prakasam said:
1 decade ago
Power= P1+P2=6+10=16
Jagat said:
1 decade ago
Power is total of each component's individual power, irrespective of how components are connected. (i.e. Series or parallel). So 6+10=16W is correct answer. Remember: Power is always additive.
Arshad said:
1 decade ago
Can you tell me how it is 4 watts? can you explain with calc?
Gk sami said:
1 decade ago
If two series-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss? 4 watts
Chandru.mdl said:
1 decade ago
If two series-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss?
Ravikumar said:
1 decade ago
Total power dissipation in parallel circuit is sum of individual power dissipation so, P=P1+P2 =6+10=16watts.
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