Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 9)
9.
If two parallel-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss?
Discussion:
28 comments Page 2 of 3.
Chandru.mdl said:
1 decade ago
If two series-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss?
Gk sami said:
1 decade ago
If two series-connected resistors dissipate 6 watts and 10 watts of power, then what is the total power loss? 4 watts
Arshad said:
1 decade ago
Can you tell me how it is 4 watts? can you explain with calc?
Jagat said:
1 decade ago
Power is total of each component's individual power, irrespective of how components are connected. (i.e. Series or parallel). So 6+10=16W is correct answer. Remember: Power is always additive.
Prasanna said:
1 decade ago
Power loss is additive whatever it is series or parallel
Akshay Prakash said:
1 decade ago
SAMI total power dissipated will be always sum of individual power.
Bharat Malik said:
1 decade ago
P=VI and V is constant in parallel circuit. So P is directly propositional to I. So P=P1+P2 So 10+6=16 watts.
Kiran said:
1 decade ago
Is the total power loss equal to the average power loss ?
Khalid usman pak said:
1 decade ago
In series circuit, always power equals p(total) = p1*p2/(p1+p2). Here the answer is 3.75.
Ravi said:
1 decade ago
We know that P = V2R relation in parallel circuit v constant. So addition gives total power.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers