Electronics - Operational Amplifiers - Discussion
Discussion Forum : Operational Amplifiers - General Questions (Q.No. 20)
20.
What is the cutoff frequency of this low-pass filter?
Discussion:
24 comments Page 2 of 3.
Shobha said:
1 decade ago
Take load resistance RL = R = 10K.
Because the formula 1/(2*pi*RL*c).
Because the formula 1/(2*pi*RL*c).
Nisha said:
1 decade ago
fc=1/(2*pi*R*C)
= 1/(2*3.14*33*10^3*0.001*10^-6)
= 4.8KHZ
= 1/(2*3.14*33*10^3*0.001*10^-6)
= 4.8KHZ
Harshith said:
1 decade ago
Please tell me cutoff frequency formula for low pass filter.
Gayatri varpe said:
3 years ago
F = 1/2πRC.
F = 1/2π*-33k*0.001*10^-6.
F = 4.8kHz.
F = 1/2π*-33k*0.001*10^-6.
F = 4.8kHz.
(1)
Sulley said:
9 years ago
I'm getting 4.8khz. So I think it should be the answer.
Abhiee said:
10 years ago
Please explain! I am not getting correct answer.
Praveen reddy said:
8 years ago
According to me, the correct ans is 4.820 khz.
SUJI said:
10 years ago
I'm also getting 4.8 khz please explain.
Mahesh said:
1 decade ago
I too getting 4.8 khz please explain.
Jsr said:
9 years ago
Cutoff frequency should be 4.8 kHz.
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