Electronics - Operational Amplifiers - Discussion
Discussion Forum : Operational Amplifiers - General Questions (Q.No. 20)
20.
What is the cutoff frequency of this low-pass filter?
Discussion:
24 comments Page 2 of 3.
Bhaskar said:
1 decade ago
Nisha could you please tell me how can we take that the value of Pi =1.34.
Daks said:
1 decade ago
F = 1/2*pi*R*C
F = 4.8Khz.
F = 4.8Khz.
Sri said:
10 years ago
vout = vin/(1+rcs).
1+(rcs)^2 = 2.
s = 1/rc.
Omega = 1/rc.
f = 1/2 pirc.
f = 4.8 KHz.
1+(rcs)^2 = 2.
s = 1/rc.
Omega = 1/rc.
f = 1/2 pirc.
f = 4.8 KHz.
Abhiee said:
10 years ago
Please explain! I am not getting correct answer.
SUJI said:
10 years ago
I'm also getting 4.8 khz please explain.
Lijo said:
9 years ago
Is it a zero crossing detector?
How can we use that normal formula of lowpass filter?
How can we use that normal formula of lowpass filter?
Jsr said:
9 years ago
Cutoff frequency should be 4.8 kHz.
ADDY said:
9 years ago
So confusing. Can anyone give us the right formula of LPF cut-off frequency?
Ramkamal Adhokari said:
9 years ago
ANS: 4.8KHZ.F = 1/2φ.r.c.
Sulley said:
9 years ago
I'm getting 4.8khz. So I think it should be the answer.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers