Electronics - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 11)
11.
What is the power in the given circuit?
Discussion:
21 comments Page 3 of 3.
Jayashri nb said:
3 years ago
P = I^2 * R.
P = 400 * 10^-3 * 400 * 10^-3 * 200.
= 32000000 * 10^-6,
= 32 * 10^6 * 10^-6,
Cancel 10^6 and 10^-6,
Ans 32.
Then P = 32watt.
P = 400 * 10^-3 * 400 * 10^-3 * 200.
= 32000000 * 10^-6,
= 32 * 10^6 * 10^-6,
Cancel 10^6 and 10^-6,
Ans 32.
Then P = 32watt.
(1)
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