Electronics - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 11)
11.
What is the power in the given circuit?
Discussion:
21 comments Page 2 of 3.
Praveen said:
1 decade ago
Given ans is wrong 32kw is the correct ans
p=i^2*r
400*400*200*10^-3
=32000=32kw
p=i^2*r
400*400*200*10^-3
=32000=32kw
Rathi said:
1 decade ago
@Praveen.
Your explanation wrong.
400 x 10^-3*400 x 10^-3*200 = 32W.
Your explanation wrong.
400 x 10^-3*400 x 10^-3*200 = 32W.
Shraddha said:
7 years ago
P=v^2*R.
V=(400/1000)*200,
V=80,
P=v^2/R.
P=(80)^2/200,
ANS: P=32w.
V=(400/1000)*200,
V=80,
P=v^2/R.
P=(80)^2/200,
ANS: P=32w.
Mainpal singh said:
1 decade ago
V=IR
P=VI
P=I*I*R
I=400/1000=0.4A
I=0.4*0.4=0.16A
P=0.16*200=32W
P=VI
P=I*I*R
I=400/1000=0.4A
I=0.4*0.4=0.16A
P=0.16*200=32W
Karthik said:
1 decade ago
V=IR
P=VI
P=I*I*R
I=400/1000=0.4A
I=0.4*0.4=0.16A
P=0.16*200=32W
P=VI
P=I*I*R
I=400/1000=0.4A
I=0.4*0.4=0.16A
P=0.16*200=32W
Omprakash said:
8 years ago
V=RI
V=400*200/10000
V=8.
P=VI
P=8*4
P=32w.
V=400*200/10000
V=8.
P=VI
P=8*4
P=32w.
M. V. NAGARAJU said:
7 years ago
Thank you all for explaining the solution.
Preethi said:
1 decade ago
Not able to understand this.
Dilipkumar M T said:
1 decade ago
This is wrong
V=I*R
V=I*R
Shawn said:
1 decade ago
What is p?
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