Electronics - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 5)
5.
What is the power in the given circuit?
Discussion:
22 comments Page 3 of 3.
Sundar said:
1 decade ago
i=v/r
p=i*i*r
r=v/r
r=7/5
r=1.4
p=1.4*(5 * 5)
p=35
p=i*i*r
r=v/r
r=7/5
r=1.4
p=1.4*(5 * 5)
p=35
Nirala anamika kumari jaiprakash said:
1 decade ago
p=(i*i)r
kvl for ckt
7=5r;
therefore r=7/5;
p=(5*5)*7/5=35;
kvl for ckt
7=5r;
therefore r=7/5;
p=(5*5)*7/5=35;
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