Electronics - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 5)
5.
What is the power in the given circuit?
Discussion:
22 comments Page 3 of 3.
Nirala anamika kumari jaiprakash said:
1 decade ago
p=(i*i)r
kvl for ckt
7=5r;
therefore r=7/5;
p=(5*5)*7/5=35;
kvl for ckt
7=5r;
therefore r=7/5;
p=(5*5)*7/5=35;
Rithin said:
1 decade ago
P=VI , P=I2R, P=V2/R
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