Electronics - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 2)
2.
In the given circuit, what will the voltage be across R3 25 
s after the switch is moved to position 2?
Discussion:
18 comments Page 2 of 2.
Mayank said:
9 years ago
Did we ignore inductance when the switch is at position one due to its very less magnitude?
Syed Shams Ul Arifeen Shah said:
9 years ago
@Mayank,
Yes we ignore the inductance because in DC source, frequency is zero so that inductor behave like short wire (XL = 2 * pi * F * L) here F = 0, XL = 0.
Yes we ignore the inductance because in DC source, frequency is zero so that inductor behave like short wire (XL = 2 * pi * F * L) here F = 0, XL = 0.
Chandhu said:
9 years ago
Open switch are there r1 then why voltage flow r3?
Chandhu said:
9 years ago
Open switch are there r1 then why voltage flow r3?
Ashfaque said:
7 years ago
@All.
An Inductor is a short circuit to dc. Then why we would be bothered about 25 microseconds. I think you are correct @Naseem.
An Inductor is a short circuit to dc. Then why we would be bothered about 25 microseconds. I think you are correct @Naseem.
Priyanka said:
6 years ago
@Clint.
I2 = I*(e^(t(R/L)).
Then I2 = 10.54*10^-3.
Therefore voltage across R3 = I2*R3 =5.905 v.
I2 = I*(e^(t(R/L)).
Then I2 = 10.54*10^-3.
Therefore voltage across R3 = I2*R3 =5.905 v.
Oliver said:
6 years ago
Yes, but to be clear, inductors are shorted (VL = 0) at DC only when STEADY STATE is reached (around 5 time constants). Though the question did not mention it, it was assumed to be that way which is why its more confusing.
Pritam said:
5 years ago
I(0-)=14/940=0.0148A....Inductor gets shorted.
At position 2.
inductor starts discharging
I(t)=I(0-)*e^(-t/T)---------> (a)
T=L/R=.1/1380=7.2*10^-5.
t/T=25*10^-6/7.2*10^-5=0.3472.
put this value in (a).
I(25us)=0.01052.
The voltage of R3=560*0.01052=5.9V.
At position 2.
inductor starts discharging
I(t)=I(0-)*e^(-t/T)---------> (a)
T=L/R=.1/1380=7.2*10^-5.
t/T=25*10^-6/7.2*10^-5=0.3472.
put this value in (a).
I(25us)=0.01052.
The voltage of R3=560*0.01052=5.9V.
(1)
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