Electronics - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 2)
2.
In the given circuit, what will the voltage be across R3 25 
s after the switch is moved to position 2?
Discussion:
18 comments Page 2 of 2.
Preetha said:
1 decade ago
@Isuru is correct.
Latha said:
1 decade ago
Naseem then how will you consider the given time?
Sambhaji gawande said:
1 decade ago
Correct solution by Isuru_R.
Isuru_R said:
1 decade ago
When the switch is at "1" position
I = 14/(120 + 820)
I = 0.01489
Then we can find the current 25us after the switch is moved to position "2" using the equation I2 = I * e^(-tR/L)
Then... from(R3* I2 ) we get the voltage across the resistor "R3".
Substitute I = 0.01489 A ; t = 25x10^(-6) s ; R = (820 + 560) ;
and L = 0.1 H
Then you will get (I2*R3) = 5.9 V , which gaves us the required solution....!
I = 14/(120 + 820)
I = 0.01489
Then we can find the current 25us after the switch is moved to position "2" using the equation I2 = I * e^(-tR/L)
Then... from(R3* I2 ) we get the voltage across the resistor "R3".
Substitute I = 0.01489 A ; t = 25x10^(-6) s ; R = (820 + 560) ;
and L = 0.1 H
Then you will get (I2*R3) = 5.9 V , which gaves us the required solution....!
(1)
Ravi said:
1 decade ago
Naseem is right.
Naseem ul aziz said:
1 decade ago
Apply voltage divider that is
when switch will be at position 2
v3=((r3)/(r3+r2))*vt=5.6 volt
when switch will be at position 2
v3=((r3)/(r3+r2))*vt=5.6 volt
Anvm said:
1 decade ago
Please tell me the solution?
Nishant said:
1 decade ago
Solution??
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