Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 8)
8.
If a 169.7 V half-wave peak has an average voltage of 54 V, what is the average of two full-wave peaks?
Discussion:
16 comments Page 2 of 2.
Nirmala said:
7 years ago
54 = vm/π
vm = 54*π
fwr = 2*vm/π
= 2 * 54*π/π = 2 * 54 = 108v.
vm = 54*π
fwr = 2*vm/π
= 2 * 54*π/π = 2 * 54 = 108v.
(3)
Rik said:
1 decade ago
I have a bit doubt in this question can someone elaborate it please.
Dinesh said:
1 decade ago
For half wave is = 169.7 and average voltage = 54.
= (54*2=108).
= (54*2=108).
SUBBU said:
1 decade ago
Generally Full Wave Having 2 Half Waves. So, 54*2=108.
M.lakshmireddy said:
5 years ago
169.7(54).
399.4(?),
?=54*399.4/169.7 = 108.0v.
399.4(?),
?=54*399.4/169.7 = 108.0v.
Arvind kumar said:
1 decade ago
For half wave 54.0 So full wave 54*2=108
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