Electronics - Diodes and Applications - Discussion

@Subbu is right,

Because .
Half wave peak=169.7 V, then full wave peak = 169.7*2 = 339.4 V.
and of two full wave peaks=2*339.4 =678.8
now,
average of Half wave peak=169.7 V is 54 of
and two(2)full wave peak=678.8/169.7 =4
therefore 4*54=216
therefor average of two full wave= 216/2=108
that means 1 full wave has 108
clue:in question there are two full wave given

Generally Full Wave Having 2 Half Waves. So, 54*2=108.

For half wave 54.0 So full wave 54*2=108

I have also doubt that in question asked that what is the average of two full-wave peaks?

I have a bit doubt in this question can someone elaborate it please.

Half wave peak=169.7 V, then full wave peak = 169.7*2 = 339.4 V.

If 169.7 V has avg voltage=54 V,

Then, 339.4 V has avg volt = (54/169.7)*339.4 = 108 V.