Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 39)
39.
What is wrong with this circuit?
Discussion:
13 comments Page 2 of 2.
Dnyaneshwar said:
1 decade ago
Thats cool. Thank you for explaination.
Shalini said:
1 decade ago
If the zener is opened, we have only R1 and R2 resister are in series.Therefore now we have a battery of 24V , R1 , R2 are all in series.
Apply voltage divider rule and find the voltage across the R2.It will come nearly 4.8v by doing calculation
i.e ., Voltage at R2=Vcc*R2/(R1+R2)
=24*2.5*10^3/(10K+2.5K)
=4.8v
This 4.8v is nearly indicated as 4.790 in the voltmeter shown in the diagram across the 2.5kohm resistor.
This is possible only if the zener is made as open.
simple:-)
Apply voltage divider rule and find the voltage across the R2.It will come nearly 4.8v by doing calculation
i.e ., Voltage at R2=Vcc*R2/(R1+R2)
=24*2.5*10^3/(10K+2.5K)
=4.8v
This 4.8v is nearly indicated as 4.790 in the voltmeter shown in the diagram across the 2.5kohm resistor.
This is possible only if the zener is made as open.
simple:-)
(1)
Preethi said:
1 decade ago
I don't know this. Please teach me.
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