Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 4)
4.
What is the reactive power in the given circuit?
Discussion:
36 comments Page 3 of 4.
Salman said:
1 decade ago
Xc=1/wc.
w=2*pi*f.
Reactive power Q=Vrms/Xc.
w=2*pi*f.
Reactive power Q=Vrms/Xc.
Engr. Shahbul said:
1 decade ago
Xc=1000/2*3.14*5*.022=1447.597ohm. P=v2/Xc=8*8/1447.597=0.0442112w, =44.21mW.
Jithin Kk said:
1 decade ago
So what about the rms value of voltage.
Prashant said:
1 decade ago
Xc=1/(2(pi)fc)
f=5k
c=0.022micro
Xc=1446.86
P=V^2/Xc=8^2/1446.86
P=0.04423VAR ~ 44.23m VAR
f=5k
c=0.022micro
Xc=1446.86
P=V^2/Xc=8^2/1446.86
P=0.04423VAR ~ 44.23m VAR
T.b.tandel said:
1 decade ago
But here given voltage r.m.s value.
Divz said:
1 decade ago
v^2 - v to the power 2
pi- const
f= freq of power source
pi- const
f= freq of power source
Sindhu said:
1 decade ago
v^ and pi and f means am not understand
Niin mukesh said:
1 decade ago
p=v^2/R
and we know,
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
and we know,
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
Rajasree said:
1 decade ago
We know that,
p=v^2/R
Here R is the reactance of capacitor which denoted by Xc
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
p=v^2/R
Here R is the reactance of capacitor which denoted by Xc
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
Nagashree said:
1 decade ago
Reactive power is the amount power that is sent back to the source from load.
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