Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 4)
4.
What is the reactive power in the given circuit?
0 VAR
691 
VAR
VAR44.23 mVAR
1.45 kVAR
Discussion:
36 comments Page 2 of 4.
Niin mukesh said:
1 decade ago
p=v^2/R
and we know,
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
and we know,
Xc=1/(2*pi*f*c)
Xc=1446.8631 ohm
P=V^2/Xc
P=64/1446.8631
P=44.233 mw
Prashant said:
1 decade ago
Xc=1/(2(pi)fc)
f=5k
c=0.022micro
Xc=1446.86
P=V^2/Xc=8^2/1446.86
P=0.04423VAR ~ 44.23m VAR
f=5k
c=0.022micro
Xc=1446.86
P=V^2/Xc=8^2/1446.86
P=0.04423VAR ~ 44.23m VAR
Gomathi said:
1 decade ago
Why they use the unit VAR (IN ANS). If it's one of the unit of mean where we use?
Nagashree said:
1 decade ago
Reactive power is the amount power that is sent back to the source from load.
Engr. Shahbul said:
1 decade ago
Xc=1000/2*3.14*5*.022=1447.597ohm. P=v2/Xc=8*8/1447.597=0.0442112w, =44.21mW.
Kiran V said:
9 years ago
Xc = 1/2 * π * f * c.
Xc = 144.75 ohm.
P = 64/144.75.
P = 0.4421 Var.
Xc = 144.75 ohm.
P = 64/144.75.
P = 0.4421 Var.
Deepika said:
1 decade ago
What is ment by reactive power? and also explaine the above problem.
Siva said:
1 decade ago
In our home we see 230 v whether it is RMRS value or anything.
Makkk said:
1 decade ago
What is the reason behind sending the power to source back?
Divz said:
1 decade ago
v^2 - v to the power 2
pi- const
f= freq of power source
pi- const
f= freq of power source
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