Electronics - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 4)
4.
What is the reactive power in the given circuit?
0 VAR
691 
VAR
VAR44.23 mVAR
1.45 kVAR
Discussion:
36 comments Page 2 of 4.
Divz said:
1 decade ago
v^2 - v to the power 2
pi- const
f= freq of power source
pi- const
f= freq of power source
T.b.tandel said:
1 decade ago
But here given voltage r.m.s value.
Prashant said:
1 decade ago
Xc=1/(2(pi)fc)
f=5k
c=0.022micro
Xc=1446.86
P=V^2/Xc=8^2/1446.86
P=0.04423VAR ~ 44.23m VAR
f=5k
c=0.022micro
Xc=1446.86
P=V^2/Xc=8^2/1446.86
P=0.04423VAR ~ 44.23m VAR
Jithin Kk said:
1 decade ago
So what about the rms value of voltage.
Engr. Shahbul said:
1 decade ago
Xc=1000/2*3.14*5*.022=1447.597ohm. P=v2/Xc=8*8/1447.597=0.0442112w, =44.21mW.
Salman said:
1 decade ago
Xc=1/wc.
w=2*pi*f.
Reactive power Q=Vrms/Xc.
w=2*pi*f.
Reactive power Q=Vrms/Xc.
Brajesh singh said:
1 decade ago
Reactive power = V(rms)*I(rms)*sin(angle b/w current and voltage).
Angle = 90 (bcoz capacitor here).
So P(reactive )= 8*(8*2*3.14*50k*.022micro).
P = 44.21 mW.
Angle = 90 (bcoz capacitor here).
So P(reactive )= 8*(8*2*3.14*50k*.022micro).
P = 44.21 mW.
San said:
1 decade ago
R IS THE REACTANCE OF THE CAPACITANCE Xc.
XC = 1/2*3.14*F*C.
= 1/6.28*5000*0.022*10^-6.
= 1/31400*0.022*10^-6.
= 1447.59.
P = R^2/Xc = 64/1447.59 = 0.0442W = 44.21mW.
XC = 1/2*3.14*F*C.
= 1/6.28*5000*0.022*10^-6.
= 1/31400*0.022*10^-6.
= 1447.59.
P = R^2/Xc = 64/1447.59 = 0.0442W = 44.21mW.
Makkk said:
1 decade ago
What is the reason behind sending the power to source back?
Krishna said:
1 decade ago
Reason behind sending back is because there is no dissipative path (load). In ideal case capacitor cannot dissipate.
Apparent power is pure resistive power whereas reactive power comes into picture because of capacitive reactance in the circuit.
P = v^2/R but now it is v^2/Z where z = R+Xc (Xc=1/2*pi*f*c)here R = 0 ideal case.
Xc=1/2*pi*f*c.
= 1/6.28*5000*0.022*10^-6.
= 1/31400*0.022*10^-6.
= 1447.59.
P = R^2/Xc = 64/1447.59 = 0.0442W = 44.21mW.
Apparent power is pure resistive power whereas reactive power comes into picture because of capacitive reactance in the circuit.
P = v^2/R but now it is v^2/Z where z = R+Xc (Xc=1/2*pi*f*c)here R = 0 ideal case.
Xc=1/2*pi*f*c.
= 1/6.28*5000*0.022*10^-6.
= 1/31400*0.022*10^-6.
= 1447.59.
P = R^2/Xc = 64/1447.59 = 0.0442W = 44.21mW.
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