Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 12)
12.
The Q point on a load line may be used to determine:
Discussion:
24 comments Page 2 of 3.
Saroj kumar mekap said:
1 decade ago
In CE configuration the general equation is:
Vce = Vcc - IcRc - IeRe.
So there is no relation to Vb. So the answer is Vc.
Vce = Vcc - IcRc - IeRe.
So there is no relation to Vb. So the answer is Vc.
Diptendu Mitra said:
1 decade ago
Vcc-IcRc-Vc=0 [Vc=Vce+Ve+Ground voltage].
or, Vcc-IcRc-(Vce+Ve+0)=0.[since,Vce=Vc-Ve & '0' is Ground voltage].
or, Vcc-IcRc-Vce-Ve=0.
or, Vcc-IcRc-Vce-Vb+Vbe=0 [Vb=Vbe+Ve, or,Ve=Vb-Vbe].
or, (Vcc-IcRc-Vce+Vbe)-Vb=0.
or, Vb=Vcc-IcRc-Vce+Vbe [Vbe=0.7v(approx),Vce=0.2v(approx)].
Now if Vce becomes equal or almost equal to Vbe , Vb=Vcc-IcRc.
So bottom line It could depend on Vb in a way.
or, Vcc-IcRc-(Vce+Ve+0)=0.[since,Vce=Vc-Ve & '0' is Ground voltage].
or, Vcc-IcRc-Vce-Ve=0.
or, Vcc-IcRc-Vce-Vb+Vbe=0 [Vb=Vbe+Ve, or,Ve=Vb-Vbe].
or, (Vcc-IcRc-Vce+Vbe)-Vb=0.
or, Vb=Vcc-IcRc-Vce+Vbe [Vbe=0.7v(approx),Vce=0.2v(approx)].
Now if Vce becomes equal or almost equal to Vbe , Vb=Vcc-IcRc.
So bottom line It could depend on Vb in a way.
Md.adil said:
1 decade ago
I think answer is wrong it should be Q(vce, ic).
Imran said:
1 decade ago
Hey guys answer is right. Vb means not base voltage it means biasing voltage. With the help of load line analysis we find the value of biasing voltage for maintain Ic at Q point. T.
Bittu said:
1 decade ago
To draw a load line we require two points (vce, ic). But considering any one of the points we cannot determine load line.
Firas said:
9 years ago
Vc = Vcc - Vce. Therefore, the answer should be option A.
Ramkamal said:
9 years ago
Ic and Vce denoted by Q point. By the Q point, we determined the value of Ic and Vcr.
Siddarthchaitanya said:
9 years ago
Load line(dc) between Ic& Vce used to bias the transistor.
Usually we consider CE configuration of transistor amplifier only.
In CE configuration input is Ib which is determined by Vb.
So answer is Vb.
Usually we consider CE configuration of transistor amplifier only.
In CE configuration input is Ib which is determined by Vb.
So answer is Vb.
HESHMAH said:
9 years ago
Q point represents current gain so, the correct option Ic that means D.
Surendran KM said:
8 years ago
I think Q point is the zero signal condition of IC and Vce hence Q pont determine IC and VCE.
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