Electronics - Bipolar Junction Transistors (BJT) - Discussion
Discussion Forum : Bipolar Junction Transistors (BJT) - General Questions (Q.No. 10)
10.
If VCC = +18 V, voltage-divider resistor R1 is 4.7 k
, and R2 is 1500, what is the base bias voltage?
, and R2 is 1500, what is the base bias voltage?Discussion:
19 comments Page 2 of 2.
Dhayamurthy said:
1 decade ago
Ans
Vcc * R2 / R1 + R2
18 * (1500 / 6200) = 4.35V
Vcc * R2 / R1 + R2
18 * (1500 / 6200) = 4.35V
Parul said:
8 years ago
Then what is across r1 resistor?
(1)
Sravani said:
8 years ago
Apply the voltage divider rule.
(1)
Mazen Mohammed said:
3 years ago
Vbb = Vcc * (R2/R1+R2) = 4.35.
(2)
RONI said:
10 years ago
Why not Vcc = (R1/R1+R2)?
Shubham k said:
6 years ago
Vcc *R2\R1+R2.
=4.35.
=4.35.
(1)
Dydie said:
1 decade ago
VBB = VCC(R2/R1+R2).
(1)
Pratul gupta said:
1 decade ago
Vb=Vcc*(r2/(r2+r1))
Sivababu said:
1 decade ago
Vcc*(R2/R2+R1)
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