Electronics - Basic Op-Amp Circuits - Discussion

Discussion Forum : Basic Op-Amp Circuits - General Questions (Q.No. 4)
4.
A digital-to-analog converter is an application of the
scaling adder
voltage-to-current converter
noninverting amplifier
adjustable bandwidth circuit
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 2 of 2.

Pragya said:   10 years ago
I want an explanation for scaling adder?

Bheema said:   9 years ago
Scaling adder means summing amplifier.
(1)

Bruhmagupta said:   4 years ago
The scaling adder is a variation of the averaging amplifier. Wherein the feedback resistor of the scaling adder is equal to or greater than the value of its input resistors. The scaling adder multiplies each input voltage by a factor of the ratio of the feedback resistor and input resistor. It then adds all of the input voltages producing a scaled sum of the inputs. That is scaling adder.

Bruhmagupta said:   4 years ago
The scaling adder is a variation of the averaging amplifier. Wherein the feedback resistor of the scaling adder is equal to or greater than the value of its input resistors. The scaling adder multiplies each input voltage by a factor of the ratio of the feedback resistor and input resistor. It then adds all of the input voltages producing a scaled sum of the inputs. That is scaling adder.

Ocelotanga said:   4 years ago
DAC has the same circuit as that of the scaling adder where each input is multiplied by the ratio of the feedback resistance to input resistance which determines its value, for example, bit 0 has Rin = 8R, bit 1 has Rin = 4R and Rf = feedback resistance = R.

Then, Vo = Rf(Vin1/Rin1 +Vin2/Rin2),
Vo = R(Vin1/8R+Vin2/4R) = (Vin1)/8 + (Vin2)/4 representing a digital signal 10 as an analog signal.

Ocelotanga said:   4 years ago
DAC has the same circuit as that of the scaling adder where each input is multiplied by the ratio of the feedback resistance to input resistance which determines its value, for example, bit 0 has Rin = 8R, bit 1 has Rin = 4R and Rf = feedback resistance = R.

Then, Vo = Rf(Vin1/Rin1 +Vin2/Rin2),
Vo = R(Vin1/8R+Vin2/4R) = (Vin1)/8 + (Vin2)/4 representing a digital signal 10 as an analog signal.


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