Electronics and Communication Engineering - Measurements and Instrumentation - Discussion
Discussion Forum : Measurements and Instrumentation - Section 1 (Q.No. 3)
3.
The coil of a moving iron instrument has a resistance of 500 Ω and an inductance of 1 H. It reads 250 V when a 250 V dc is applied. If series resistance is 2000 Ω, its reading when fed by 250 V, 50 Hz ac will be
Answer: Option
Explanation:
Discussion:
30 comments Page 3 of 3.
Prabhas said:
9 years ago
The value of φ = (22/7).
Karthik said:
9 years ago
I didn't get the value of 2pifl, here f = 50hz, l = 1H, and how to find pi values can you elaborate this please.
Shyam babu yadav said:
9 years ago
I can't understand the measuring of AC current. Why you take j314.16? Please explain that.
Zameer said:
9 years ago
Why didn't you consider the 500 ohms of moving iron at the calculation of ac?
Ravinder said:
10 years ago
Still not understood because if 2pifl = what its not j314.6 then how?
Ritika said:
1 decade ago
Measuring of alternate current sine wave form so imaginary axis will also take as i-axis.
Current = Voltage/Resistance.
Current = Voltage/Resistance.
Khasim chotu said:
1 decade ago
In dc there will be no term of inductive reactance.
So that meter current reads for ac = (i) = v/r = 250/(2500+j 314.16) = 0.09922 A.
J 314.6 because Inductive reactance = 2*pi*f*L.
NOW voltage(v) = ir = 0.09922*2500 = 248 v.
So that meter current reads for ac = (i) = v/r = 250/(2500+j 314.16) = 0.09922 A.
J 314.6 because Inductive reactance = 2*pi*f*L.
NOW voltage(v) = ir = 0.09922*2500 = 248 v.
Cheetha said:
1 decade ago
Inductive reactance = 2*pi*f*L.
Annu kumari said:
1 decade ago
From where you put the value of j314.16?
Suma said:
1 decade ago
I can't understood the measuring of ac current. Why you put j314.16?
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