Electronics and Communication Engineering - Measurements and Instrumentation - Discussion
Discussion Forum : Measurements and Instrumentation - Section 1 (Q.No. 3)
3.
The coil of a moving iron instrument has a resistance of 500 Ω and an inductance of 1 H. It reads 250 V when a 250 V dc is applied. If series resistance is 2000 Ω, its reading when fed by 250 V, 50 Hz ac will be
Answer: Option
Explanation:
Discussion:
30 comments Page 2 of 3.
Shyam babu yadav said:
9 years ago
I can't understand the measuring of AC current. Why you take j314.16? Please explain that.
Surya said:
9 years ago
Ac impedance is Z = R + jXl, so here j314.16 = 2 * pi * 50 * 1 as given inductance is 1H.
Ester said:
9 years ago
I've calculated the 2 * pi * f * L and I got 0.8883.
I didn't get the 0.09922. why?
I didn't get the 0.09922. why?
Shikha said:
9 years ago
Inductance value is added in dc it's right but why resistance value is different?
Zameer said:
9 years ago
Why didn't you consider the 500 ohms of moving iron at the calculation of ac?
Bijendra said:
9 years ago
I have doubt in Meter current of AC?
Please enplane more about this part.
Please enplane more about this part.
Ravinder said:
10 years ago
Still not understood because if 2pifl = what its not j314.6 then how?
Suma said:
1 decade ago
I can't understood the measuring of ac current. Why you put j314.16?
Prabhas said:
9 years ago
At last why they have divided AC value and DC value? Please help me.
LAVANYA said:
6 years ago
I am not understanding this, Please explain it clearly to get it.
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