Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 11 (Q.No. 22)
22.
The Boolean function A + BC is reduced form of
Discussion:
1 comments Page 1 of 1.
Prasad said:
4 years ago
A.A+A.C+B.A+B.C.
= A+A.C+B.A+B.C,
= A(1+B)+A.C+B.C,
= A+A.C+B.C.
= A(1+C)+B.C,
= A+B.C.
= A+A.C+B.A+B.C,
= A(1+B)+A.C+B.C,
= A+A.C+B.C.
= A(1+C)+B.C,
= A+B.C.
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