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Electronics and Communication Engineering - Electromagnetic Field Theory

Exercise : Electromagnetic Field Theory - Section 3
36.
A wavelength of 1 mm could be expected in
VLF
HF
EHF
SHF
Answer: Option
Explanation:
No answer description is available. Let's discuss.
37.
The numerical value of directivity of current element of half-wave dipole is 1.76 and 2.15 dB respectively. The directive gain of half-wave dipole over current element will be
3.91 dB
1.95 dB
0.39 dB
0.195 dB
Answer: Option
Explanation:

2.15 - 1.76 = 0.39 db.

38.
The maximum effective aperture of an antenna which is operating at wavelength of 2 m and has directivity of 100 is
15.92
31.84
2.18
3.184
Answer: Option
Explanation:

39.
The waveguides compared to equivalent transmission lines at low frequency are
able to carry more power
less noisy
having lower attenuation
all of the above
Answer: Option
Explanation:
No answer description is available. Let's discuss.
40.
The current distribution of a half wave dipole is
uniform
sinusoidal
triangular
complex
Answer: Option
Explanation:
No answer description is available. Let's discuss.
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