Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 1 (Q.No. 16)
16.
The access time of a word in 4 MB main memory is 100 ms. The access time of a word in a 32 kb data cache memory is 10 ns. The average data cache bit ratio is 0.95. The efficiency of memory access time is
9.5 ns
14.5 ns
20 ns
95 ns
Answer: Option
Explanation:

Access time = 0.95 x 10 + 0.05 x 100.

Discussion:
34 comments Page 4 of 4.

Prajwal said:   6 years ago
Thank you @Bikram and @Pooja.

Ali Muhammad said:   5 years ago
You explained in a good manner. Thank you @ Bikram.

Tshering Dorji said:   5 years ago
That means the access time from the main memory is 100ns or 100ms? I think time is 100ns and not 100ms.

Please anyone explain it clearly.
(4)

Amit kumar said:   4 years ago
@Bikram.

Good explanation. Thanks.


Post your comments here:

Your comments will be displayed after verification.