Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 1 (Q.No. 16)
16.
The access time of a word in 4 MB main memory is 100 ms. The access time of a word in a 32 kb data cache memory is 10 ns. The average data cache bit ratio is 0.95. The efficiency of memory access time is
9.5 ns
14.5 ns
20 ns
95 ns
Answer: Option
Explanation:

Access time = 0.95 x 10 + 0.05 x 100.

Discussion:
34 comments Page 3 of 4.

Daleep said:   1 decade ago
Please mention the formula used above.

Anonym said:   8 years ago
1-0.095=0.05 according to the formula

Sree said:   9 years ago
Please mention the formula used here.

Amit kumar said:   4 years ago
@Bikram.

Good explanation. Thanks.

Amrita said:   9 years ago
Thank you the explanation @Bikram.

Padmaja said:   9 years ago
Thank you @Bikram Kesharee Nayak.

Mahesh said:   10 years ago
Can you please explain clearly?

Nithya said:   1 decade ago
Can you please explain clearly?

Prajwal said:   6 years ago
Thank you @Bikram and @Pooja.

Vanajavivek said:   6 years ago
Thank you @Bkram and @Pooja.


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