Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 44)
44.
A memory system of size 16 k bytes is to be designed using memory chips which have 12 address lines and 4 data lines each. The number of such chips required to design the memory system is
Answer: Option
Explanation:
.
Discussion:
19 comments Page 2 of 2.
Anilkumar said:
1 decade ago
What is the exact formula used?
Preethi said:
9 years ago
The numerator is in bits and denominator is in bytes. How could it be possible?
KUMAR said:
9 years ago
2^16 = 2^10 * 2^6.
1024 * 64 BYTE.
1024 * 64 * 8 BIT.
1024 * 64 BYTE.
1024 * 64 * 8 BIT.
Shikha said:
10 years ago
Because in digital byte means 8.
= 2^10 = 1026 is called kilo.
= 2^10 = 1026 is called kilo.
Jayasankar said:
10 years ago
16k means 16*1024 but how 8 will comes?
Sai said:
1 decade ago
16k means 16*1000 but you used 1024 why?
Krishna said:
1 decade ago
16K bytes = 16*1024*8.
12 address lines = 2^12 bytes.
4 data lines.
Now the simplification is direct.
12 address lines = 2^12 bytes.
4 data lines.
Now the simplification is direct.
Daleep said:
1 decade ago
Logic behind this calculation?
Athi said:
1 decade ago
How did the answer come?
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