Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 7)
7.
In 2's complement representation the number 11100101 represents the decimal number
Answer: Option
Explanation:
A = 11100101. Therefore A = 00011010 and A' = A + 1 = 00011011 = 16 + 8 + 2 + 1 = 27. Therefore A = -27.
Discussion:
54 comments Page 4 of 6.
Ramakrishna said:
9 years ago
2's compliment represent of any number is - (2's compliment of the original number).
Priyanka said:
9 years ago
I think this negative sign has been confirmed from the MSB and LSB bits of the given number and not the 1's complement number.
After finding answer through the appropriate orocedure as discuss above, check the given number, and give the particilar +ve or -ve sign to the answer. Thats it.
After finding answer through the appropriate orocedure as discuss above, check the given number, and give the particilar +ve or -ve sign to the answer. Thats it.
Renu said:
9 years ago
How did you get - symbol. Please explain clearly.
Vishal said:
10 years ago
Yes @Aslam its +27.
Aslam said:
10 years ago
They asked decimal equivalent of 2's complement of 11100101 which is 00011011 here MSB is 0, hence +27.
Sita said:
10 years ago
In the given binary form msb bit is 1 should keep '-' sign. Msb bit is 0 then you should keep positive sign.
B.Mallesh goud said:
10 years ago
Why we use -ve sign instead of +ve sign?
Anshika said:
10 years ago
How come it is -ve sign. It should be +ve?
Can anyone explain me?
Can anyone explain me?
E&tc group D.Y. Patil ambi pune said:
1 decade ago
-(2^4=16, 2^3=8, 2^1=2, 2^0=1) = -27.
Geetha adainjan said:
1 decade ago
2's com -11100101. Then 1's com is 11100101-1=1100100.
Then the required binary no is 0011011. According to binary to decimal conversion the position value is 128, 64, 32, 16, 8, 4, 2, 1 here binary 1 is present in 16+8+2+1=27.
Then the required binary no is 0011011. According to binary to decimal conversion the position value is 128, 64, 32, 16, 8, 4, 2, 1 here binary 1 is present in 16+8+2+1=27.
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