Electronics and Communication Engineering - Digital Electronics - Discussion

It is used in short form that you are seeing 16+8+2+1. It is basically the conversion of binary in decimal where 1 is there we add all that positions by taking 2^4+2^8+2^1+2^0 power here represents the position of bits.

I agree with the given answer -27.

The Correct option is +27.

For a two's compliment, we add +1 with the ones compliment.

So, from two's compliment to one's compliment we have to subtract -1.

I think +27 is correct.

The correct answer is +27.
i.e option D.

Here they just asked that 2's compliment of the decimal number is 11100101 so what is that decimal number?

If you see MSBbit is one so the decimal number should be in negative not positive.

Iy should be +27 because the msb obtain after the calculation is 0 which indicates its sign bit as +ve.

Msb bit decides the sign of the number. After finding the 2's compliment the msb bit is 0, hence the negative sign. If it was 1 it would hav been +27.

How to convert a signed binary two's complement?
1110 0101(2) to an integer in decimal system (in base 10)

1. Is this a positive or a negative number?
In a signed binary two's complement, first bit (the leftmost) indicates the sign,
1 = negative, 0 = positive.
1110 0101 is the binary representation of a negative integer, on 8 bits.


2. Get the binary representation in one's complement:
* Run this step only if the number is negative *
Subtract 1 from the binary initial number:
1110 0101 - 1 = 1110 0100


2. Get the binary representation of the positive (unsigned) number:
* Run this step only if the number is negative *
Flip all the bits in the signed binary one's complement representation (reverse the digits) - replace the bits set on 1 with 0s and the bits on 0 with 1s:
!(1110 0100) = 0001 1011


3. Map the unsigned binary number's digits versus the corresponding powers of 2 that their place value represent:

27
0
26
0
25
0
24
1
23
1
22
0
21
1
20
1

4. Multiply each bit by its corresponding power of 2 and add all the terms up:
0001 1011(2) = (0 * 27 + 0 * 26 + 0 * 25 + 1 * 24 + 1 * 23 + 0 * 22 + 1 * 21 + 1 * 20)(10) = (0 + 0 + 0 + 16 + 8 + 0 + 2 + 1)(10) = (16 + 8 + 2 + 1)(10) = 27(10).

5. If needed, adjust the sign of the integer number by the first digit (leftmost) of the signed binary:
1110 0101(2) = -27(10).

At all many have a doubt for the negative sign doubt so I ll try to solve it.

In digital electronics the MSB bit (the leftmost bit) is the sign bit and its negative if it is set to 1 or if it is set to 0 it is positive. So look at the MSB perform the operation and represent it as positive or negative depending on the sign bit.