Electronics and Communication Engineering - Automatic Control Systems - Discussion
Discussion Forum : Automatic Control Systems - Section 1 (Q.No. 3)
3.
For the system in the given figure. The transfer function C(s)/R(s) is
Answer: Option
Explanation:
Transfer function = (G1 + 1) G2 + 1 = G1 G2 + G2 + 1.
Discussion:
20 comments Page 2 of 2.
Khetendra Vashishtha said:
9 years ago
Forward path = 2 (G2 & G1G2).
Loop = 1(G2).
Using Masons formula:
then TF = (G2 + G1.G2)/(1 - G2).
Loop = 1(G2).
Using Masons formula:
then TF = (G2 + G1.G2)/(1 - G2).
(1)
R C Pandey said:
1 decade ago
@Anish.
You are calculating TF between C and are. So there is only one forward path and that is G1G2.
You are calculating TF between C and are. So there is only one forward path and that is G1G2.
Roshan said:
1 decade ago
There is only one loop.
Number of +ve loop = 1.
So, (G1G2 + G2) / (1 - G2).
Number of +ve loop = 1.
So, (G1G2 + G2) / (1 - G2).
Fizza said:
10 years ago
What is the difference between transfer function and characteristic equation?
Praveen said:
10 years ago
Can anyone say the correct answer please as soon as possible?
Yogendra said:
6 years ago
No loop is there, 3 forward path is g2 and g1g2 and 1 only.
Hamed said:
9 years ago
Not correct.
The answer is [(G1 + 1) G2]/[1 - G2].
The answer is [(G1 + 1) G2]/[1 - G2].
Ayushri said:
10 years ago
Answer is wrong.
Answer: (G1G2/((1+G1)(1+G2))).
Answer: (G1G2/((1+G1)(1+G2))).
Beu said:
1 decade ago
No. of fwd path = 3.
No. of loop = 0.
No. of loop = 0.
RITHIKA said:
1 decade ago
Can anyone please solve it briefly ?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers