Electronics and Communication Engineering - Automatic Control Systems - Discussion
Discussion Forum : Automatic Control Systems - Section 1 (Q.No. 3)
3.
For the system in the given figure. The transfer function C(s)/R(s) is
Answer: Option
Explanation:
Transfer function = (G1 + 1) G2 + 1 = G1 G2 + G2 + 1.
Discussion:
20 comments Page 2 of 2.
Fizza said:
10 years ago
What is the difference between transfer function and characteristic equation?
Praveen said:
10 years ago
Can anyone say the correct answer please as soon as possible?
R C Pandey said:
1 decade ago
@Anish.
You are calculating TF between C and are. So there is only one forward path and that is G1G2.
You are calculating TF between C and are. So there is only one forward path and that is G1G2.
Anish said:
1 decade ago
If anyone knows any answer which is different from my answer please explain it clearly so that everyone will understand.
ANISH KUMAR said:
1 decade ago
Answer (G2+G1G2)/(1-G2).
Explanation:
Forward path = 2 (G2 & G1G2).
Loop = 1(G2).
Using Masson formula:
We get (G2+G1G2)/(1-G2);
Explanation:
Forward path = 2 (G2 & G1G2).
Loop = 1(G2).
Using Masson formula:
We get (G2+G1G2)/(1-G2);
(1)
Roshan said:
1 decade ago
There is only one loop.
Number of +ve loop = 1.
So, (G1G2 + G2) / (1 - G2).
Number of +ve loop = 1.
So, (G1G2 + G2) / (1 - G2).
Rajarajan said:
1 decade ago
The above answer is not correct. Number of forward path = 2.
Number of loops = 1.
Answer is [G1G2+G2]/[1-G2].
Number of loops = 1.
Answer is [G1G2+G2]/[1-G2].
Bitra hanumantharao said:
1 decade ago
Number of forward paths are 2.
Number of loops are 2.
That too no loop are not repeated.
The transfer function of the system is: G1G2/ (1-G1G2-G2).
Number of loops are 2.
That too no loop are not repeated.
The transfer function of the system is: G1G2/ (1-G1G2-G2).
RITHIKA said:
1 decade ago
Can anyone please solve it briefly ?
Beu said:
1 decade ago
No. of fwd path = 3.
No. of loop = 0.
No. of loop = 0.
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