Electronic Devices - Power Amplifiers - Discussion
Discussion Forum : Power Amplifiers - General Questions (Q.No. 2)
2.
Calculate VB2.
Discussion:
11 comments Page 2 of 2.
JJ T said:
1 decade ago
Hello, I am curious as to why 9.3V is the answer.
If we have 20 Vcc across a branch of resistance totaling R1 + D1 + D2 + R2, which is 1200 + 0.7 +0.7 + 1200 = 2401.4 Ohm.
If I run a voltage divider on this at VB2, I am getting 1200/2401.4(20) = which is 9.99V.
I tried to do it using voltage drops as well and I am still getting about 10V at VB2.
Could you please let me know if I am doing something wrong?
If we have 20 Vcc across a branch of resistance totaling R1 + D1 + D2 + R2, which is 1200 + 0.7 +0.7 + 1200 = 2401.4 Ohm.
If I run a voltage divider on this at VB2, I am getting 1200/2401.4(20) = which is 9.99V.
I tried to do it using voltage drops as well and I am still getting about 10V at VB2.
Could you please let me know if I am doing something wrong?
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