Electronic Devices - Op-Amp Applications - Discussion

Well, here the second term, [Rf/R3xRf/R1] contains two gains multiplied, so it is very obvious that two systems have to be cascaded [basic control system] and the first term can be easily provided by using the concept of superposition.

So, B seems to be right.

V1 is passed through an inverting opamp with resistors R3 and Rf.

So output voltage =-(Rf/R3)*V1.

Now the output of above stage is given as input to an inverting summer along with V2 as second input.

Here the output of the inverting stage is connected with R1 and
V2 is connected with resistor R2.

So final o/p=(- Rf/R2)V2 + (- Rf/R3)(- Rf/R1)V1.