Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 8)
8.
Determine the peak value of the current through the load resistor.
Discussion:
13 comments Page 2 of 2.
Shrikrishna said:
1 decade ago
Actually resistance is RL+2K=4k
Now voltage across load is 10-.7v=9.3v
so i=9.3/4
2.325
Now voltage across load is 10-.7v=9.3v
so i=9.3/4
2.325
Digvijay said:
1 decade ago
Answer is correct, 10V-0.7V(drop across diode)/4k(2k series with 2k)
Sumanth said:
1 decade ago
Answer should be 2.5 mA rather than 2.325 mA.
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