Electronic Devices - DC Biasing-BJTs - Discussion
Discussion Forum : DC Biasing-BJTs - General Questions (Q.No. 6)
6.
Calculate the voltage across the 91 k
resistor.

Discussion:
12 comments Page 2 of 2.
Petrus said:
7 years ago
The Rc resistor is in series with the whole circuit so since Ic=beta Ib and Ie = (beta+1)Ib
using KVL Vcc = Vc + Ve +Vbe +Vb thus Vcc = IcRc 9IeRc+ IbRb + Vbe = Ib ( betaRc+Rb +Re +BetaRe +Vbe).
Thus Ib = 18 / (3.3*75 + 0.510 +0.510*76 + 210 = 36. 147 micro A.
Thus, 91000*36.147 micro A = 3.289 V.
using KVL Vcc = Vc + Ve +Vbe +Vb thus Vcc = IcRc 9IeRc+ IbRb + Vbe = Ib ( betaRc+Rb +Re +BetaRe +Vbe).
Thus Ib = 18 / (3.3*75 + 0.510 +0.510*76 + 210 = 36. 147 micro A.
Thus, 91000*36.147 micro A = 3.289 V.
(5)
Nootnoot said:
6 years ago
Why do you use 0.510 instead of 510 ohms?
(2)
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