Electronic Devices - DC Biasing-BJTs - Discussion
Discussion Forum : DC Biasing-BJTs - General Questions (Q.No. 6)
6.
Calculate the voltage across the 91 k
resistor.
resistor. 
Discussion:
12 comments Page 2 of 2.
Kaushal wagh said:
1 decade ago
3.3(b+1)Ib+ 201 Ib + 0.7 +0.510(b+1)Ib = 18.
3.3*76 Ib + 201 Ib + 0.7 +0.510 * 76 Ib = 18.
250.8 Ib + 201Ib+38.76 Ib = 17.3.
Ib= 0.035 mA.
So voltage = 0.035 * 91.
=3.20 v.
3.3*76 Ib + 201 Ib + 0.7 +0.510 * 76 Ib = 18.
250.8 Ib + 201Ib+38.76 Ib = 17.3.
Ib= 0.035 mA.
So voltage = 0.035 * 91.
=3.20 v.
(1)
Swati singh said:
1 decade ago
For D.C. analysis all capacitors will be open circuit then equations will be,
18 = 3.3(b+1)I1+(91+110)I1+0.7+0.510I1.
I1 = 0.0352mA.
Hence voltage across 91 kohm resistor will be,
91 kohm*0.0352mA = 3.2V.
18 = 3.3(b+1)I1+(91+110)I1+0.7+0.510I1.
I1 = 0.0352mA.
Hence voltage across 91 kohm resistor will be,
91 kohm*0.0352mA = 3.2V.
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