Electronic Devices - BJT Devices - Discussion
Discussion Forum : BJT Devices - General Questions (Q.No. 13)
13.
Use this table of collector characteristics to calculate 
ac at VCE = 15 V and IB = 30 
A.
ac at VCE = 15 V and IB = 30 A. 
Discussion:
17 comments Page 2 of 2.
Pasha said:
1 decade ago
Ic it come from the graph we can see the graph where the two axis there one is Ic(mA) and other Vce.
Look the graph where the curve turn to the Ib 30uA.
And Ic measured in (mA)3.
Look the graph where the curve turn to the Ib 30uA.
And Ic measured in (mA)3.
Khan said:
1 decade ago
As it seem from graph that at Vce=15v, Ie>3ma so beta must be greater than 100, ie 106.
Nikhil said:
1 decade ago
From graph.
Ic=3mA and Ib given is 30uA.
So, B= Ic/Ib = 3mA/30uA = 100A.
Ic=3mA and Ib given is 30uA.
So, B= Ic/Ib = 3mA/30uA = 100A.
Priyam srivastava said:
1 decade ago
Beta = Ic/Ib , because beta comes in CE case so in this case input is base and output is collector so current amplification beta equals to collector current/base current.
So, beta = 100
So, beta = 100
Avi said:
2 decades ago
I think Ic is 3.2 mA. SO, THE ANSWER MUST BE 106.
Ankita said:
2 decades ago
Please explain how Ic is being calculated.
Emery said:
2 decades ago
Vce = 15v at Ib = 30uA is equal Ic = 3mA,
so, beta = Ic/Ib
= 3mA/30uA
= 100...^_^
so, beta = Ic/Ib
= 3mA/30uA
= 100...^_^
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