Electronic Devices - Bipolar Junction Transistors - Discussion
Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 1)
1.
Refer to this figure. Determine the minimum value of IB that will produce saturation.
0.25 mA
5.325 
A
A1.065 A
A10.425 A
ADiscussion:
25 comments Page 2 of 3.
Albert Einstein said:
8 years ago
It's a constant for saturation of BJT; VCE=0.2V. much like how we know that VBE=0.7 or 0.3 (mostly 0.7).
Unknown said:
10 years ago
The Circuit is Fixed biased not emitter stabilized. It does not have resistor on the emitter (Re).
Ragavendar said:
9 years ago
Find ic first,
Ic = Vcc /Rc = 2.2mA / 4.7kohm.
Then find Ib from formula Bdc = Ic/Ib.
Ic = Vcc /Rc = 2.2mA / 4.7kohm.
Then find Ib from formula Bdc = Ic/Ib.
Bem said:
1 decade ago
Given:
B = 200.
Rc = 4.7.
Rb = 1.2.
from KCL,
Vin=IbRb+Vbe+Vcb.
B = 200.
Rc = 4.7.
Rb = 1.2.
from KCL,
Vin=IbRb+Vbe+Vcb.
Aklilu kendu said:
8 years ago
I don't understand this equation how we get 0.2? Explain it.
Rahul said:
5 years ago
I don't understand this. Please explain in a simple way.
Yasaswini said:
7 years ago
I can't understand. Please, anyone explain me.
Manikantan said:
1 decade ago
That is the constant saturation value of Vce?
Anonymous said:
1 decade ago
Ic(sat) = Vcc/Rc,
Ib(min) = Ic(sat)/beta.
Ib(min) = Ic(sat)/beta.
Amomis said:
7 years ago
IC(sat)= Vcc/RC.
IB = IC(sat)/β.
IB = IC(sat)/β.
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