Electronic Devices - Bipolar Junction Transistors - Discussion
Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 1)
1.
Refer to this figure. Determine the minimum value of IB that will produce saturation.
0.25 mA
5.325 
A
A1.065 A
A10.425 A
ADiscussion:
25 comments Page 2 of 3.
Isha said:
9 years ago
Use VCE = 0.2V for the saturated region and apply KCL in the outer loop and get Ic and use beta to get Ib.
JOE said:
9 years ago
Everyone who has posted thus far is incorrect.
If you assume that Vc = 0.2V then Vce = 0.2 This means that the circuit is already in saturation mode and BIc = Ib does not apply.
The BIc = Ib equation only applies to transistors in forward active mode.
If you assume that Vc = 0.2V then Vce = 0.2 This means that the circuit is already in saturation mode and BIc = Ib does not apply.
The BIc = Ib equation only applies to transistors in forward active mode.
Ahire s said:
9 years ago
Nice explanations, Thank you all.
Aklilu kendu said:
8 years ago
I don't understand this equation how we get 0.2? Explain it.
Albert Einstein said:
8 years ago
It's a constant for saturation of BJT; VCE=0.2V. much like how we know that VBE=0.7 or 0.3 (mostly 0.7).
KingLevis said:
7 years ago
Vce at sat is btn 0.2 to 0.3 for silicon diode transistor.
From Ic sat=(Vcc-Vce)/Rc.
(10-0.2)/4700ohms.
Ic=2.085mA.
But Ib=Ic/Bdc.
2.085/200.
Ib=10.425micro-ampere.
Assumptions assume Vce=0.2V.
From Ic sat=(Vcc-Vce)/Rc.
(10-0.2)/4700ohms.
Ic=2.085mA.
But Ib=Ic/Bdc.
2.085/200.
Ib=10.425micro-ampere.
Assumptions assume Vce=0.2V.
(1)
Amomis said:
7 years ago
IC(sat)= Vcc/RC.
IB = IC(sat)/β.
IB = IC(sat)/β.
Thaya said:
7 years ago
Here, IB = VBB - VBE/RB.
Yasaswini said:
7 years ago
I can't understand. Please, anyone explain me.
ENHLE. said:
6 years ago
VCC = RC.IC(sat) + VCE(sat).
IC(sat) = VCC-VCE(sat)/RC.
IC(sat) = (10-0.2)/4700.
IC(sat) = 2.085 micro Amps.
IC(sat) = Bdc.IB(min).
IC(sat) = (200)(2.085 micro Amps).
IC(sat) = 10.43 mcro amps.
IC(sat) = VCC-VCE(sat)/RC.
IC(sat) = (10-0.2)/4700.
IC(sat) = 2.085 micro Amps.
IC(sat) = Bdc.IB(min).
IC(sat) = (200)(2.085 micro Amps).
IC(sat) = 10.43 mcro amps.
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