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Electronic Devices - Bipolar Junction Transistors - Discussion

Discussion Forum : Bipolar Junction Transistors - General Questions (Q.No. 1)
Bipolar Junction Transistors
1.
Refer to this figure. Determine the minimum value of IB that will produce saturation.

0.25 mA
5.325 A
1.065 A
10.425 A
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 2 of 3.
Albert Einstein said:   8 years ago
It's a constant for saturation of BJT; VCE=0.2V. much like how we know that VBE=0.7 or 0.3 (mostly 0.7).
Aklilu kendu said:   8 years ago
I don't understand this equation how we get 0.2? Explain it.
Ahire s said:   9 years ago
Nice explanations, Thank you all.
JOE said:   9 years ago
Everyone who has posted thus far is incorrect.
If you assume that Vc = 0.2V then Vce = 0.2 This means that the circuit is already in saturation mode and BIc = Ib does not apply.

The BIc = Ib equation only applies to transistors in forward active mode.
Isha said:   9 years ago
Use VCE = 0.2V for the saturated region and apply KCL in the outer loop and get Ic and use beta to get Ib.
Ragavendar said:   9 years ago
Find ic first,

Ic = Vcc /Rc = 2.2mA / 4.7kohm.

Then find Ib from formula Bdc = Ic/Ib.
Unknown said:   10 years ago
The Circuit is Fixed biased not emitter stabilized. It does not have resistor on the emitter (Re).
Eric Orellana Romero said:   1 decade ago
About of first answer, the equation ic=B*ib is not valid for saturation zone in a bjt transistor. In this zone, bjt behavior is not lineal.
Bem said:   1 decade ago
Given:

B = 200.
Rc = 4.7.
Rb = 1.2.

from KCL,
Vin=IbRb+Vbe+Vcb.
Anonymous said:   1 decade ago
Ic(sat) = Vcc/Rc,

Ib(min) = Ic(sat)/beta.
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