Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 10)
10.
A transformer with a 110 V primary has a 15:1 turns ratio. The load resistance, RL, is 120 
. What is the approximate voltage across the load?
. What is the approximate voltage across the load?Discussion:
53 comments Page 6 of 6.
Prashanth nive.. said:
1 decade ago
Given value N1:N2 = 15 : 1 (That is N1 = 15, N2 = 1).
Turns ratio = (N1/N2) = 15/1 (ratio > 1 ; Step down transformer).
As you said, V2/V1 = N2/N1.
V2/110v = 1/15.
V2 = 110v/15.
V2 = 7.3333... volts.
Hope this will help to clear your doubts. Have a nice day!
Turns ratio = (N1/N2) = 15/1 (ratio > 1 ; Step down transformer).
As you said, V2/V1 = N2/N1.
V2/110v = 1/15.
V2 = 110v/15.
V2 = 7.3333... volts.
Hope this will help to clear your doubts. Have a nice day!
Jyotindra said:
1 decade ago
We know k = n2/n1.
And here 15:1 is given,
Therefore k = 15:1.
Or n2/n1 = 15/1 = v2/v1.
So we get v2 = (n2/n1)*v1,
= (15/1)*110 = 1650v answer.
But there is no option. Therefore we go on this way,
n1:n2 = 15:1.
We get v2 = 7.333 v.
And here 15:1 is given,
Therefore k = 15:1.
Or n2/n1 = 15/1 = v2/v1.
So we get v2 = (n2/n1)*v1,
= (15/1)*110 = 1650v answer.
But there is no option. Therefore we go on this way,
n1:n2 = 15:1.
We get v2 = 7.333 v.
Duryodhan kumar mandal said:
1 decade ago
N1/N2 = V1/V2.
Than putting value,
15:1 = 110:v2.
=> v2 = 110*1/15.
=> v2 = 7.33v.
Than putting value,
15:1 = 110:v2.
=> v2 = 110*1/15.
=> v2 = 7.33v.
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